Answer :
The proportion of carbon within the pattern if 0. 6006 g of baco3 was shaped
BaCO3 = 0.6006 g/ 197.34 g/mol=zero.003043
Moles carbon in the sample = 0.003043
mass C = zero.003043 mol x 12.011 g/mol=zero.03656 g
% C = 0.03656 x 100/ 0.2121 =17.23
Natural compounds are a substance that includes covalently- bonded carbon and hydrogen and often with different elements. organic compounds examples are benzoic Acid, fragrant compounds, benzoic aldehyde, propanoic acid, butanoic acid, malonic acid, amines, heterocyclic compounds, VOC, benzoic acid, and diethyl malonate.
Of the numerous forms of organic compounds, four important classes are located in all residing things: carbohydrates, lipids, proteins, and nucleic acids.
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