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Systolic blood pressure for a group of women is normally distributed, with a mean of 115 and a standard deviation of 9. Find the probability that a woman selected at random has the following blood pressures. (Round your answers to four decimal places.) (a) greater than 130 (b) less than 108 (c) between 108 and 122

Answer :

The probability that the blood pressure of woman is more than 130 by given normal distribution is 0.9505

What is z-value?

The standard score in statistics is the amount of standard deviations that a raw score deviates from or exceeds the mean of the phenomenon being observed or assessed. Standard scores are positive for raw scores above the mean.

We are given a normal distribution with a mean value 115 and standard deviation 9

And we are asked to find the probability that a woman selected at random has blood pressure greater than 130

We first find the z-value

z= (x-μ)/σ

z= (130-115)/9

z= 15/9

z= 1.6666

Now the corresponding value is

Probability is 0.95

Hence the probability is 95%

TO learn more about the probability please refer the following link

https://brainly.com/question/24756209

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