Answer :
The equation of the line that passes through the points (2, 15) and (5, 21) is y = 2x + 11
The coordinates of the first point = (2, 15)
The coordinates of the second point = (5, 21)
The slope of the line = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Substitute the values in the equation
The slope of the line = (21-15) / (5-2)
= 6 / 3
= 2
The slope intercept form is
y = mx + b
Substitute the values
15 = 2(2) + b
15 = 4 + b
b = 15 - 4
b = 11
Substitute the values in the equation
y = 2x + 11
Therefore, the equation of the line in slope intercept form is y = 2x + 11
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