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A 30 kg chair initially at rest on a horizontal floor requires a 160 N horizontal force to set it in motion. Once the chair is in motion, a 125 N horizontal force keeps it moving at a constant velocity. The acceleration of gravity is 9.81 m/s 2 . a) What is the coefficient of static friction between the chair and the floor? 017 (part 2 of 2) 10.0 points b) What is the coefficient of kinetic friction between the chair and the floor?

Answer :

(a). The chair's dynamic friction factor with the floor is = 0.602.

(b). The chair's as well as the floor's kinetic friction factor is = 0.475.

What is a simple definition of velocity?

The metre per second (m/s) is the accepted unit of velocity magnitude (also known as speed).

Briefing:

a)Let's practice using Newton's second law. In the reference system, the x axis is perpendicular to the axis and parallel to the floor.

Y Axis

        N-W = 0

        N = W

X axis

         F-fr = ma

The formula for the friction force is

  fr = μN

The acceleration is zero where the movement starts.

Let's replace

F = μ (mg) = 0

F = μ mg

μ = F / mg

μ = 160/30 9.81

μ = 0.602

b) The formula is the same in this instance, but the friction is kinetic.

    μ = F2 / mg

    μ = 125/30 9.81

    μ = 0.475

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