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A 75-W light source consumes 75 W of electrical power. Assume it converts electricity to light at 600nm wavelength with a power efficiency of 20%. a) calculate the power of emitted light at 600nm. b) calculate the frequency of the emitted light; c) calculate the energy of a single emitted photon, express the answer in both Joule and eV; d) calculate how many photons at 600 nm are emitted per second.

Answer :

Part a) Power of emitted light at 600nm:  P = 75-Watt

Part b) Frequency of the emitted light; f = 4.99 x 10¹⁴ Hz.

Part c: Energy of a single emitted photon;E = 3.310 x 10⁻¹⁹ J

Part d) Number of photons emitted per second: 2.3 x 10²⁰ .

Explain the term photon?

  • Photons are the tiniest electromagnetic energy packets known as quanta of light.
  • Whether you are viewing this on a page or a screen, streaming of photons are sending the text' images to your eyes.

Part a) Power of emitted light at 600nm:

Power P = 75-Watt

Part b) Frequency of the emitted light;

Frequency = speed of light/wavelength of light

f = c/λ

f = 3 x 10⁸ / 600 x 10⁻⁹  Hz

f = 4.99 x 10¹⁴ Hz

Part c: Energy of a single emitted photon;

Energy = hc/λ = hf

h = plank's constant  = 6.626 x 10⁻³⁴ J.s

E = hf

E = 6.626 x 10⁻³⁴ x  4.99 x 10¹⁴

E = 3.310 x 10⁻¹⁹ J

Part d) Number of photons emitted per second:

N = P/hf

N = 75/3.310 x 10⁻¹⁹

N = 2.3 x 10²⁰

Thus, the number of photons emitted per second: 2.3 x 10²⁰ .

To know more about the  photon, here

https://brainly.com/question/17227537

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