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A loop of wire is at the edge of a region of space containing a uniform magnetic field B. The plane of the loop is perpendicular to the magnetic field. Now the loop is pulled out of this region in such a way that the area A of the coil inside the magnetic field region is decreasing at the constant rate . That is, dA/dt=−c , with c >0 . The induced emf in the loop is measured to be V. What is the magnitude B of the magnetic field that the loop was in? Express your answer in terms of some or all of the variables A ,c , and V. Homework Equations :
ϵ=|dΦm.dt| Φm=AB ϵ=lvB

Answer :

The magnitude of the magnetic filed B at the loop is found as  V/c.

Explain the term magnetic flux?

  • A measurement of a total magnetic field that traverses a specific area is called magnetic flux.
  • It is a helpful tool for explaining how the magnetic force affects things inhabiting a certain area.

For the stated question-

The formula for magnetic flux;

Φ = BA

In which,

  • B = magnetic field
  • A = area

Now,

Differentiate the flux with respect to time as putting B as constant;

dΦ/dt = B•dA/dt

Using Faraday's law, EMF induced is;

E = -dΦ/dt

However, we prefer to describe it in terms of V and E.M.F., which are also used to refer to voltage or potential difference.

V = -dΦ/dt

Thus, potential difference be-

-V = B•dA/dt

In term of a given area dA/dt = - c

-V = B•(-c)

V = Bc

B = V/c

Therefore, the magnitude of the magnetic filed B at the loop is found as  V/c.

To know more about the magnetic flux, here

https://brainly.com/question/16234377

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