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Assume a population in Hardy-Weinberg equilibrium for a character trait with these genotypic frequencies: AA = 0.25, Aa = 0.50, and aa = 0.25. If you remove all the homozygous dominants and allow the remaining population to reproduce (again under Hardy-Weinberg conditions), what will be the frequency of homozygous dominants in the next generation?

Answer :

If you remove all the homozygous dominants and allow the remaining population to reproduce ,The frequency of homozygous dominants in the next generation is 0.11.

The genotypic frequencies: AA = 0.25, Aa = 0.50, and aa = 0.25.

I just simply used the probability rule. p(Aa) = 1/2

Probability to get homozygous dominantsby crossing AAx aa = 1/4

so (1/2) x (1/4) = 1/8 = 0.125 which is pretty close to 0.11

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