Answer :
The probability that the second is a club, given that the first is not a club is 0.1911
According to the question,
We have a ordinary deck
An ordinary deck contain 52 cards
Number of club an ordinary have = 13
Let the first event of not getting a club at first draw be "A"
and "B" for getting a club at second draw
P( not getting a club) = P(A) = 1 - P(getting a club)
=> 1 - 13/52
=> 39/52
Now , We are drawing card without replacement
Number of cards we have after first draw = 51
P(getting a club) = P(B) = 13 / 51
The probability that the second is a club, given that the first is not a club
P(A).P(A)=> 39/52 . 13/51
=> 507/2652
=> 0.1911
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