Puck B's kinetic energy is 2 times puck A's kinetic energy.
The energy an item has as a result of motion is known as kinetic energy. If we wish to accelerate an item, we must use force. We must put in effort in order to apply force.
Briefing:
Let the,
mass of puck A =m
mass of puck B = 2 m
The initial speed for both the pucks is the same as u and the distance is the same for both as s.
Let the tension is T for the same.
Then, the kinetic energy is given as,
KE= [tex]\frac{1}{2}[/tex] M[tex]V^{2}[/tex]
where M is the mass of an object
and v is the velocity of an object
as the speed is the same for both mass A and B so kinetic energy will depend on only the mass of the object.
[tex]\frac{KE OF A}{KE OF B}[/tex] = [tex]\frac{1}{2} M_{A} V_A^{2}[/tex] /[tex]\frac{1}{2} M_{B} V_B^{2}[/tex]
on putting the values of masses a and b
we get,
[tex]\frac{KE OF A}{KE OF B}[/tex] = [tex]\frac{1}{2}[/tex]
KE OF B= 2(KE OF A)
As a result, we can say that puck B has kinetic energy that is twice that of puck A.
to know more about kinetic energy visit:
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the complete question is:
Puck B has twice the mass of puck A. Starting from rest, both pucks are pulled the same distance across frictionless ice by strings with the same tension. Compare the final kinetic energies of pucks A and B.
