If z is a standard normal variable, the probability that z is less than 1.13 is given by: A. 0.8708.
In Statistics, the standard normal distribution table is designed and developed to provide only the area to the left of a specified z-score.
Additionally, since z-score (z₁) and z-score (z₂) are generally symmetric about z = 0 and are negatives of one another, then, by symmetry, the area to the right of z-score (z₂) is always equal to the area to the left of z-score (z₁).
This ultimately implies that, the total areas under a standard normal distribution curve in two tails can be determined by calculating the area to the left of z-score (z₁) and multiplying the value by two (2).
From the z-score table, the area to the left of z-score (z₁ = 1.13) is the same as the probability that z is less than 1.13 and this is given by:
Area to the left of z-score (z₁ = 1.13) = 0.8708.
Probability, P(z ≤ 1.13) = 0.8708.
Read more on z-scores here: brainly.com/question/17180058
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