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Write the chemical formula for (a) ruthenium(III) sulfide (b) scandium fluoride (c) osmium(VIII) oxide (d) manganese(II) sulfide (e) platinum(IV) chloride.

Answer :

The chemical formula for ruthenium (III) sulfide, scandium fluoride, osmium (VIII) oxide, manganese (II) sulfide, and platinum (IV) chloride are Ru₂S₃, ScF₃, OsO₄, MnS, and PtCl₄.

Ionic compounds are formed from metal and non-metal ions. The metal ions have positive ions and the non-metal ions have negative ions. To achieve stability, they use electrons together. The name of the ionic compound called the chemical formula.

A. Ruthenium (III) sulfide

  • Positive ion ruthenium (III) = Ru⁺³
    Will release three electrons
  • Negative ion sulfide = S⁻²
    Will gain two electrons
  • Need 2 ions ruthenium (III) and 3 ions sulfide.
  • Ru₂S₃

B. Scandium fluoride

  • Positive ion scandium = Sc⁺³
    Will release three electrons
  • Negative ion fluoride = F⁻
    Will gain one electron
  • Need 1 ion scandium and 3 ions fluoride.
  • ScF₃

C. Osmium (VIII) oxide

  • Positive ion osmium (VIII) = Os⁺⁸
    Will release eight electrons
  • Negative ion oxide = O⁻²
    Will gain two electron
  • Need 1 ion scandium and 4 ions oxide.
  • OsO₄

D. Manganese (II) sulfide

  • Positive ion manganese (II) = Mn⁺²
    Will release two electrons
  • Negative ion sulfide = S⁻²
    Will gain two electron
  • Need 1 ion scandium and 1 ion sulfide.
  • MnS

E. Platinum (IV) chloride

  • Positive ion platinum (IV) = Pt⁺⁴
    Will release four electrons
  • Negative ion chloride = Cl⁻
    Will gain two electron
  • Need 1 ion platinum and 4 ions chloride.
  • PtCl₄

Learn more about the ionic compounds here: brainly.com/question/977324

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