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a 5.0 kg obkect slides fown a surfaced incline at an angle of 30 degrees from the horizontal. The total distance moved by the object along the plane is 10 meters. The work done on the object by the normal force of the surface is:_____.
a. 0.25 kJ
b. zero
c. 0.50 kJ
d. 0.43 kJ
e. 0.58 kJ

Answer :

Tutorconsortium631go

B. Zero, The work done on the object by the normal force of the surface is zero. work done is measured in joules (J) and force is measured in newtons (N).

How to solve?

The body is inclined at θ=30°,

s=10m, m=5kg

Work done by the object = FsCosθ

but the surface is a friction-less, this means coefficient of friction =0

F=μR

F=0*R

F=0

W=FScosθ

W=0*SCosθ

Work done =0

What is the difference between work and Work done?

There is connection between work and energy, in a sense that when there is a net force doing work on an object, the object's kinetic energy will change by an amount equal to the work done.

What is Work done on the system?

If force is applied on a system and the it experiences a displacement then the work is said to be done on the system. If a system applies a force on something and causes displacement then the work is said to be done by the system.

Learn more about displacement here:

https://brainly.com/question/29307794

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