Answer :
The induced emf between the two sides of the shark's head is 44*10-6 volts. the process whereby changes in magnetic flux cause a coil to develop a potential difference.
Here's the complete question:
A scalloped hammerhead shark swims at a steady speed of 1.0 m/s with its 83-cm-wide head perpendicular to the earth's 52 μT magnetic field. What is the magnitude of the emf induced between the two sides of the shark's head? Express your answer using two significant figures.
How to solve ?
Given:
The speed of scalloped hammerhead shark is: va=1.0ms
The width of head is:
wa=83cm=0.83m.
The magnetic field is:
Ba=52μT=53×10−6T
The expression for the change in area through which magnetic field moves is,
ΔAa=Δla.wa
Here,
Δla and wa are change in length and width respectively.
The expression for the speed of scalloped hammerhead shark is,
va=Δla/Δt
Here ,
Δt is time interval.
The expression for the magnetic flux is,
Δϕa=Ba.ΔAa
The expression for the induced emf by using the Faraday's law is,
ea=Δϕa/Δt
Solving for the induced enf:
ea=Ba.Δla.wa/Δt
⟹Ba.wa.Δla/Δt⟹Ba.wa.va
The expression for the magnitude of emf induced between the two sides of shark's head is,
ea=Ba.wa.va
Solving for the magnitude of emf induced between the two sides of shark's head:
ea=53×10−6T×0.83m×1.0m/s⟹43.99×10−6V⟹≈44×10−6V
Thus the magnitude of emf induced between the two sides of shark's head is 44×10−6V.
What distinguishes induced emf from electromagnetic fields?
According to Faraday's Law, if a magnetic flux across a loop changes, an induced emf results. The term "motional emf" is used to describe an emf that is changing because a conductor is moving in some way in a magnetic field.
What is another name for EMF?
When no current is flowing, electromotive force equals the potential difference. the fact that both EMF and potential difference (V) are expressed in volts, but they are not the same thing.
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