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The maker of an automobile advertises that it takes 11 seconds to accelerate from 25 kilometers per hour to 75 kilometers per hour. Assuming constant acceleration, compute the distance, in meters, the car travels during the 11 seconds. Round your answer to two decimal places. 168.06 m 152.78 m 305.56 m 76.39 m 32.73 m

Answer :

The value of the acceleration is 1.26 m/s² for the automobile advertised by the makers.

Explain the equation of motion?

  • motion is shift in a body's orientation or position over time.
  • Translation is defined as movement across a line or a curve.
  • Rotation is a motion that modifies a body's orientation.

Time t = 11 sec

Initial velocity u = 25 kmph

u = (25 × 1000)/(60 × 60) = 6.9 m/s

final velocity v = 75 kmph

v = (75 × 1000)/(60 × 60) = 20.83 m/s

From the first equation of motion;

v = u + at

Put the values;

20.83 = 6.9 + 11a

20.83 - 6.9 = 13a

11a = 13.93

a = 13.93 / 11

a = 1.26 m/s²

Thus, the value of the acceleration is 1.26 m/s² for the automobile advertised by the makers.

To know more about the equation of motion, here

https://brainly.com/question/25951773

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