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Luke has blue and red ballsEvery day he wins 2 blue balls and loses 3 red onesAfter 5 days he has the same amount of blue and red ballsAfter 9 days, he has twice as many red balls as blue ballsHow many red balls did he have at the beginning?

Answer :

The number of red balls Luke has at the start is 47.

blue ball per day = 2

red ball per day = -3 ('-' ve sign as he is loosing them)

let the number of red balls be represented by r

let the number of blue balls be represented by b

 

after 5 days

b+ 10 = r -15 -(i)

After 9 days

b + 18 =2(r-27)-(ii)

subtracting (i) from (ii)

b + 18 - b - 10 = 2r - r - 54 +15

8 = r - 39

r = 39 + 8

r = 47

The number of red balls Luke has at the start is 47

Learn more about 2-variable Linear Equations at:

brainly.com/question/29796485

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