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the small piston of a hydraulic lift (see figure below) has a cross-sectional area of 3.30 cm2, and its large piston has a cross-sectional area of 204 cm2. what downward force of magnitude f1 must be applied to the small piston for the lift to raise a load whose weight is fg

Answer :

The downward force of magnitude must be applied to the small piston for the lift to raise a load whose weight is Fg = 15.0 kN is 225N.

Given that,

The small piston of a hydraulic lift has a cross-sectional of 3.00 cm^2.

And its large piston has a cross-sectional area of 200 cm^2.

Based on the above information, the calculation is as follows:

Here we use the Pascal's principle,

........... (1)

Here

F denoted Force exerted on the larger piston,

f denoted force that applied to the smaller piston,

A denoted cross-sectional area of the larger piston,

And, a denoted cross-sectional area of the smaller piston.

Now

=  225 N

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