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a person, sunbathing on a warm day, is lying horizontally on the deck of a boat. her mass is 59.5 kg, and the coefficient of static friction between the deck and her is 0.566. assume that she is moving horizontally, and that the static frictional force is the only force acting on her in this direction. (a) what is the magnitude of the static frictional force when the boat moves with a constant velocity of 8.16 m/s? (b) the boat speeds up with an acceleration of 1.00 m/s2, and she does not slip with respect to the deck. what is the magnitude of the static frictional force that acts on her? (c) what is the magnitude of the maximum acceleration the boat can have before she begins to slip relative to the deck?

Answer :

Tutorconsortium630go

a) since a=0 therefore, friction force =0

b) friction = 59.5 × 1 =59.5 N.

c)maximum acceleration = 0.566 × g =5.54 m/s².

What is Friction force?

The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction. There are various kinds of friction: Two solid surfaces in touch are opposed to one another's a relative lateral motion by dry friction.

What is acceleration?

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities. The direction of the net force acting on an object determines the direction of its acceleration.

Hence, (a) since a=0 therefore, friction force =0, (b) friction = 59.5 × 1 =59.5 N, (c)maximum acceleration = 0.566 × g =5.54 m/s².

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