Answer :
The initial temperature of the water and copper is 22.51°C.
Mass of ice m = 14 g
We know, 1g = 0.001 kg
So, m= (14 x 0.001)kg = 0.014kg
Mass of water ml = 300g = (300 x 0.001)kg = 0.3kg
Mass of copper calorimeter m₂ = 200g = (200 × 0.001) kg = 0.21 kg
Specific heat of water s₁ = 4186 [tex]\frac{J}{kg . C}[/tex]
Specific heat of ice s₂ = 2100 [tex]\frac{J}{kg.C}[/tex]
Specific heat of copper s₃ = 387 [tex]\frac{J}{kg.C}[/tex]
Latent heat of fusion of water L = 3.33 x 10⁵ [tex]\frac{J}{kg}[/tex]
Initial temperature of ice T₁ = - 10°C
Initial temperature of water copper is T₂
Final temperature of the system is T = 18 °C
From equilibrium in heat
Heat gain by ice to become 0°C of ice +0°C of ice become 0 °C of water + 0°C of water become 18°C of water = heat loss by copper and water
ms₂ (0°-(-10°)) + mL + ms₁ (T -0°) = m₁s₁ (T₂-18°) + m₂s₃ (T2 - 18°)
∴ 0.014 × 2100 × 10 + 0.014 × 3.33 × 10⁵+ 0.014 × 4186 × 18 = 0.3 × 4186 × (T₂- 18 ) + 0.2 × 387 × ( T₂ -18 )
∴ 6010.87 = 1333.2(T₂ - 18)
∴ T₂ - 18 = 6010.87 / 1333.2 = 4.51
∴ T₂ = ( 18 + 4.51 )
∴ T₂ = 22.51° C
So, the initial temperature of the water and copper is 22.51°C.
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