Answer :
Based on the combination technique,
1. The position of wire 3
2. The magnitude and direction of current in wire 3
Combination method:
In statistics, the mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter is know a combination method.
Given,
Here we have the three long wires hang vertically. The distance between wire 1 and wire 2 is 23.0 cm On the left, wire 1 carries an upward current of 1.50 A. To the right, wire 2 carries a downward current of 3.60 A. Wire 3 is to be located such that when it carries a certain current, each wire experiences no net force.
And now we need to find the position of wire 3 and the magnitude and direction of the current in wire 3.
As per the given question, we know that the
=> Current in wire 1, i1 =1.2A upward
=> Current in wire 2, i2=5A downward
And the distance between wire 1 and 2 is calculated is
=> 20cm = 0.2m
Here the current is calculated as
=> F/l = μo•i1•i3/2πx
So,
=> F/l=6×10⁻⁶N/m
=> 6×10⁻⁶ = μo•i1•i3/2πx
=> 6×10⁻⁶ =4π×10⁻⁷×1.2×i3/(2π×0.0632)
When we do Cross multiply,
=> 6×10⁻⁶×2π0.0632=4π×10⁻⁷×1.2×i3
=> 2.383×10⁻⁶=4π×10⁻⁷×1.2×i3
=> i3= (2.383×10⁻⁶)/(4π×10⁻⁷×1.2)
Therefore, i3= 1.58A and it's direction is downward.
To know more Combination method here.
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