Which of the following complex numbers is equal to (5 + 12i) β (9i^2 β 6i), for i β -1 ?

Complex number equal to (5 + 12i) β (9i^2 β 6i), for i = β -1 is 14 + 18i.
Complex numbers are the numbers that are expressed in the form of a+ib where, a,b are real numbers and βiβ is an imaginary number called βiotaβ. The value of i = (β-1)
Given number is (5 + 12i) β (9i^2 β 6i).
We know that i^2 = -1.
Using this we get number = 5+12i+9+6i
= 14+18i
So the required number is 14 + 18i.
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