The resulting dipole is 0.56 N/C
Charges of the dipole, q = 30
Separation distance between the charges, d = 0.0010 m
Separation distance between the center and the charge, d' = d/2 = 0.25
x = 4.0 m
y = 0.0 m
Now,
The electric field due to the positive charge on the right of the origin:
E = k{q/(d'+x)²}
where
k = Coulomb's constant = 9 x 10⁹ Nm²/C²
Now,
E = 1124.72 N/C
Similarly, electric field due to the negative charge:
E' = k{q/(x-d')²}
E' = -1125.72 N/C
Thus
E(total) = E' - E = 0.56 N/C
Therefore, the positive charge is 0.56 N/C.
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