Answer :
The acceleration of the object with mass 4.5 x 10-5 kg and charge 9 x 10-9 C is 8 x 10-4 m/s²
The acceleration of an object in an electric field is given by the equation:
a = (F/m) = (qE/m)
where F is the force acting on the object, m is the mass of the object, q is the charge of the object, and E is the electric field strength.
Therefore, the acceleration of the object with mass 4.5 x 10-5 kg and charge 9 x 10-9 C under the influence of an electric field of magnitude 5000 V/m is:
a = (qE/m) = (9 x 10-9 C x 5000 V/m)/(4.5 x 10-5 kg)
a = 8 x 10-4 m/s²
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