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in 2001, the united states produced 51 percent of its electricity in the amount of 1.878 x 10^12 kwh from coal fired power plants. taking the average thermal efficiency to be 34 percent, determine the amount of thermal energy rejected by the coal-fired power plants in the united states that year.

Answer :

The amount of thermal energy rejected by the coal-fired power plants in the united states is [tex]3.646.10^{12} kWh[/tex].

What is thermal efficiency?

The ratio of the heat produced by a heat engine to the total heat units in the fuel consumed that's what is meant by thermal efficiency .

[tex]nth=\frac{Wcoal}{Qin}\\nth=\frac{Wcoal}{Qout-Wcoal} 23\\Qout=\frac{Wcoal}{nth} -Wcoal[/tex]

[tex]Qout=\frac{Wcoal}{nth} -Wcoal\\Qout=\frac{1.878.10^{12} }{0.34} -1.878.10^{12}\\=3.646.10^{12} kWh[/tex]

Therefore, the amount of thermal energy rejected by the coal-fired power plants in the united states is [tex]3.646.10^{12} kWh[/tex].

To learn more about thermal efficiency from the given link.

https://brainly.com/question/14287776

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