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a 0.60 kg ball is moving horizontally with a speed of 5.7 m/s when it strikes a vertical wall. the ball rebounds with a speed of 2.7 m/s. what is the magnitude of the change in linear momentum of the ball?

Answer :

We can use the following equation to solve this problem:

Δp=m∣Vi−Vf∣

(Where p is the momentum change, m is mass, Vi is initial velocity, and

Vf is final velocity)

Substitute the values given to us in the question:

Δp=(0.6)∣(5.7−(−2.7)∣

Δp=4.9 kg.m/s

Final answer: 4.9kg.m/s.

The change in momentum (Δp) is defined as the change in the mass times the velocity of an object. A force is required to change the momentum of an object. This applied force can increase or decrease momentum, or even change the orientation of an object.

Learn more about momentum:

https://brainly.in/question/1535814

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