Answer :
1.30×10 W is the maximum allowable heat rate that can be generated by the electronic device to maintain the temperature below 85°C for an unfinned package.
Write the equation conduction resistance
Rcond = d/kA.........(1)
Consider the following and substitute the values:
From the table of 'thermo physical properties of selected nonmetallic solids' at a temperature of 300K.
The thermal conductivity of Silicon carbide, k is given by 490 W/m - K
Dimension of the electronic device,
W=10x10⁻⁶m
Find the cross-sectional area
A=W²
= (10x10⁻⁶)² m²
Rcond = 100×10⁻⁹/490×(10×10⁻⁶)^2
= 2.04 K/W
The equation Convection resistance is given as follows:
Rconv = 1/hA
Consider the following and substitute the values:
Heat transfer coefficient of coolant
h= 1×10 W/m² K and
A= (10×10⁻⁶)² m²
Rcond = 1/10⁵x(10x10⁻⁶)^2
= 1×10⁵ K/W
Find the heat rate by using the following equation
q= T1- Tinfinity/ Rcond + Rconv...........(3)
= 2(85-20)/ (2.04+10⁵)
q = 1.30×10 W
Thus, the maximum allowable heat rate that can be generated by the electronic device to maintain the temperature below 85°C for the unfinned package is 1.30×10 W.
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