Answer :
The probability that a child chosen at random from the class has both a cat and a dog is 1/10.
Suppose b is the total number of kids that have both:
• children having a cat Only must be 14 - b
• children having a dog Only must be 19 - b
We also get:
We also know there are 30 kids, therefore
⇒ (14 - b) + b + (19 - b) = 30
⇒ 33 - b = 30
⇒ b = 3
Consequently, we now understand:
3/30 = 1/10
Know more about probability at:
https://brainly.com/question/24756209
#SPJ4
