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what is the formula for the following arithmetic sequence 12 6 0; what is the value of the 11th term in the following geometric sequence? -5, -10, -20, -40; arithmetic formula

Answer :

a. The formula for the nth term of the given arithmetic sequence is -

[tex]a_n[/tex] = 6(1 - n).

b.  The 11th term of the given Geometric sequence is -5120.

a. We are the given set of numbers 12, 6, 0,... which is in arithmetic sequence with first term [tex]a_1[/tex] = 12 and the common difference

d = 12 - 6 = 6 - 0 = 6

Hence, d = 6.

We have to find the formula for the nth term of the given arithmetic sequence.

the formula to find the nth term in Geometric Progression is

[tex]a_n=a_1[/tex] + d(n−1)

Substituting the values [tex]a_1[/tex]  = 12 and d = 6, we will get,

[tex]a_n[/tex] = 12 + 6(n - 1)

[tex]a_n[/tex] = 12 + 6n -6

[tex]a_n[/tex] = 6 - 6n

[tex]a_n[/tex] = 6(1 - n)

Hence, the formula for the nth term of the given arithmetic sequence is [tex]a_n[/tex] = 6(1 - n).

b. We are the given set of numbers -5,-10,-20,-40, which is in Geometric Sequence with first term [tex]a_1[/tex] = - 5 and the common ratio -

[tex]r=\frac{-40}{-20}=\frac{-20}{-10}=\frac{-10}{-5}=2[/tex]

hence, r = 2

the formula to find the nth term in Geometric Progression is

[tex]a_n=a_1 \cdot r^{n-1}[/tex]

Now we will find the 11th term in the given geometric sequence.

Use now [tex]a_1[/tex] = -5 and r = 2 and n = 11 in the formula as follows-

[tex]a_n=a_1 \cdot r^{n-1}[/tex]

[tex]a_{11}= -5 \cdot(2)^{11-1}[/tex]

[tex]a_{11}=-5 \cdot(2)^{10}[/tex]

[tex]a_{11}=-5 \cdot 1024[/tex]

[tex]a_{11}[/tex] = - 5120

Hence, the 11th term of the given Geometric sequence is -5120.

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