Answer :
Answer:
Here, centre (h, k) = (2, - 3) and radius r = 5 units. Hence, the equation of a circle with centre at (2, - 3) and radius 5 units is x 2 + y 2 − 4 x + 6 y − 12 = 0 .
Answer:
Here, centre (h, k) = (2, - 3) and radius r = 5 units. Hence, the equation of a circle with centre at (2, - 3) and radius 5 units is x 2 + y 2 − 4 x + 6 y − 12 = 0 .