The equation of the line is perpendicular to the line y = -4x - 3 and passes through the point (10, 6) is y = 1 / 4 x + 7 / 2.
How to find the equation of a line?
The equation of a line can be represented in slope intercept form as follows:
y = mx + b
where
Therefore, the equation of the line is perpendicular to the line y = -4x - 3 and passes through the point (10, 6).
Perpendicular lines follows the rule:
m₁ m₂ = -1
-4m₂ = -1
m₂ = 1 / 4
Let's find the y-intercept of the equation using (10, 6)
y = 1 / 4 x + b
6 = 1 / 4 (10) + b
6 = 5 / 2 + b
b = 6 - 5 / 2
b = 12 - 5/ 2
b = 7 / 2
Therefore, the equation of the line is y = 1 / 4 x + 7 / 2
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