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A 20-cm wrench is used to loosen a bolt. The force is applied 0. 20m from the bolt. It takes 100n to loosen the bolt when the force is applied perpendicular to the wrench. How much force would it take if the force was applied at a 30o angle from perpendicular? round-off your answer to the nearest whole number.

Answer :

The force that it will take if applied perpendicular at 30° = 58 N

According to the formula of torque = τ and force = F,

τ =  r x F x sinθ --- equation 1

Given, F = 100 N , r = 0.2 m (r = radius)

We have to find the force when θ (angle) = 30°

Putting value in equation 1,

τ = 0.2 x 100 x sin (30°)

τ = 10 Nm

Value of torque from here = 10 Nm

Now to calculate the force perpendicular at 30° the equation will change as,

τ = r x F x cosθ --- equation 2

10 = 0.2 x F x cos 30°

Taking τ on the right side and F on left,

F = 10/ (0.2 x cos 30°)

F = 57.73 N

F = 58 N

Therefore, The force that it will take if applied perpendicular at 30° = 58 N

To learn more about this question on forces and torque,

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