Given AB= 20, BV=12, VA=14 and SR is a mid segment, find the given lengths

Given:
AB= 20, BV=12, VA=14 and SR is a mid segment.
To find:
The lengths of SR and AR.
Solution:
SR is a mid segment. So, SR is parallel to the non-included side BV and the length of SR is half of BV.
[tex]SR=\dfrac{1}{2}BV[/tex]
[tex]SR=\dfrac{1}{2}(12)[/tex]
[tex]SR=6[/tex]
SR is a mid segment. So, it divides the included sides in two equal parts. It means R is the midpoint of VA.
[tex]AR=\dfrac{1}{2}VA[/tex]
[tex]AR=\dfrac{1}{2}(14)[/tex]
[tex]AR=7[/tex]
Therefore, the measure of SR is 6 units and the measure of AR is 7 units.