Answer :
Answer:
kβ’(8k3-5k2+5k-5)β’(k+1)β’(23k2-30k-6)
βββββββββββββββββββββββββββββββββββ
2β’(3k5-50k4-5)
Step-by-step explanation:
You should get this sorry if I am wrong but I am pretty sure this is the answer.