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A 45 g bug is hovering in the air. A gust of wind
exerts a force F = (4.0 î – 6.0j) x 10^-2 N on
the bug.

How much work is done by the wind as the bug undergoes displacement r = (8.0î - 8.0j) m?

Answer :

Onyebuchinnajigo

The work-done by the wind as the bug undergoes the displacement is 80 J.

The given parameters;

  • Mass of the bug, m = 45 g
  • Force exerted, F = (4.0 î – 6.0j) x 10⁻² N
  • Displacement of the bug, r = (8.0î - 8.0j) m

The work-done by the wind as the bug undergoes the displacement is obtained by finding the dot product of the force and the displacement;

Work done = F. r

Work done = (4.0 î – 6.0j) x 10⁻² . (8.0î - 8.0j)

Work done = (32i²) + (48j²)

Work done = 32(1) + 48(1)

Work done = 80 J.

Thus, the work-done by the wind as the bug undergoes the displacement is 80 J.

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