[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Let's solve ~
Perimeter of square is :
[tex]\qquad \sf \dashrightarrow \:4 \times side \: length[/tex]
so, we can take side length as a, and solve for a ~
[tex]\qquad \sf \dashrightarrow \:4a = 60[/tex]
[tex]\qquad \sf \dashrightarrow \:a = 60 \div 4[/tex]
[tex]\qquad \sf \dashrightarrow \:a = 15[/tex]
Now, since we know the side length. let's find Area of square :
[tex]\qquad \sf \dashrightarrow \: {15}^{2} [/tex]
[tex]\qquad \sf \dashrightarrow \:area = 225 \: m {}^{2} [/tex]
