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Which equation represents a circle that contains the point (–2, 8) and has a center at (4, 0)? distance formula: startroot (x 2 minus x 1) squared (y 2 minus y 1) squared endroot (x – 4)2 y2 = 100 (x – 4)2 y2 = 10 x2 (y – 4)² = 10 x2 (y – 4)² = 100

Answer :

Raphealnwobigo

The equation of a circle that contains the point (–2, 8) and has a center at (4, 0) is (x - 4)² + y² = 10²

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

The circle contains the point (–2, 8) and has a center at (4, 0), hence:

[tex]radius=\sqrt{(0-8)^2+(4-(-2))^2}=10\ units[/tex]

The equation is:

(x - 4)² + (y - 0)² = 10²

(x - 4)² + y² = 10²

The equation of a circle that contains the point (–2, 8) and has a center at (4, 0) is (x - 4)² + y² = 10²

Find out more on equation at: https://brainly.com/question/2972832

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BigRedJuicego

Answer:

A

Step-by-step explanation:

the first one is the answer

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