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Answer :

First, express the interval in decimal form:

(0.302, 0.44)

Now find the average value of the endpoints of the interval. This will give us the value of p:

[tex]p=\frac{0.302+0.44}{2}=0.371[/tex]

Now find the semi difference of the endpoints to have the value of ME:

[tex]ME=\frac{0.44-0.302}{2}=0.069[/tex]

Now express the interval in the required form:

[tex](0.32,0.44)=0.371\pm0.069[/tex]

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