Answer :
To solve this equation remember how to solve for x in logarithmic equations. For example:
[tex]\begin{gathered} \log x=a \\ 10^{\log x}=10^a \\ x=10^a \end{gathered}[/tex]Do the same procedure for the given equation.
[tex]\begin{gathered} \log (5-x)=0.5 \\ 10^{log(5-x)}=10^{0.5} \\ 5-x=\sqrt[]{10} \\ -x=\sqrt[]{10}^{}-5 \\ x=5-\sqrt[]{10}^{} \end{gathered}[/tex]x has a value of 5-sqrt(10).