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In ΔIJK, \overline{IK}
IK
i extended through point K to point L, \text{m}\angle JKL = (5x-3)^{\circ}m∠JKL=(5x−3)
∘
, \text{m}\angle KIJ = (2x8)^{\circ}m∠KIJ=(2x8)
∘
, and \text{m}\angle IJK = (x-1)^{\circ}m∠IJK=(x−1)
∘. Find \text{m}\angle JKL. M∠JKL

Answer :

The measure of m∠JKL is found to be 22 degrees.

From the given question we are given the following:

Exterior angle

m ∠ J K L = ( 5 x − 3 )°

Interior angles;

m∠KIJ=(2x+8)°

m∠IJK=(x−1)°

Note that the sum of interior angles is equal to the exterior angles;

Hence, m∠KIJ +m∠IJK = m∠JKL

Substitute the given values;

2x+8 + x -1 = 5x - 3

3x + 7 = 5x - 3

Collect like terms;

3x - 5x = -3-7

-2x = -10

x = 10/2

x = 5

Get m∠JKL;

m∠JKL = 5x - 3

m∠JKL= 5(5)-3

m∠JKL = 25-3

m∠JKL = 22°

∴ Hence the measure of m∠JKL is 22 degrees.

Learn more about angles here;

https://brainly.com/question/25716982

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